Phase Relation in a Pure Inductor

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Phase Relation in a Pure Inductor

Phase Relation in a Pure Inductor

The voltage-current relation in the case of an inductor is given by:

v(t)=Ldi(t)dtv(t) = L\frac{di(t)}{dt}

where:

  • LL = inductance
  • i(t)i(t) = current
  • v(t)v(t) = voltage

Sinusoidal Current Through an Inductor

Consider the current function:

i(t)=Imsinωti(t) = I_m \sin \omega t

Differentiating with respect to time,

di(t)dt=Imωcosωt\frac{di(t)}{dt} = I_m \omega \cos \omega t

Substituting into the voltage equation,

v(t)=LImωcosωtv(t) = L I_m \omega \cos \omega t

Using the trigonometric identity,

cosωt=sin(ωt+90)\cos \omega t = \sin\left(\omega t + 90^\circ\right)

Therefore,

v(t)=ωLImsin(ωt+90)v(t) = \omega L I_m \sin\left(\omega t + 90^\circ\right)

Let,

Vm=ωLImV_m = \omega L I_m

Hence,

v(t)=Vmsin(ωt+90)v(t) = V_m \sin\left(\omega t + 90^\circ\right)

Phase Relationship

If we draw the waveforms for both voltage and current as shown in Fig. 2.11, we can observe the phase difference between these two waveforms.

Voltage and current in pure inductor

In a pure inductor, voltage and current are out of phase.

The voltage leads the current by:

9090^\circ

or equivalently,

The current lags behind the voltage by 9090^\circ.


Impedance of a Pure Inductor

The impedance is the ratio of voltage to current.

Z=VIZ = \frac{V}{I}

For a pure inductor,

Z=VmIm=ωLZ = \frac{V_m}{I_m} = \omega L

The inductive reactance is represented by:

XL=ωLX_L = \omega L

where:

  • ω=2πf\omega = 2\pi f
  • LL = inductance

Thus,

XL=2πfLX_L = 2\pi fL

The impedance of a pure inductor is represented in complex form as:

Z=jXLZ = jX_L

or

Z=jωLZ = j\omega L

Hence, a pure inductor has an impedance whose value is:

jωLj\omega L

Characteristics of Pure Inductive Circuit

  • Current lags voltage by 9090^\circ.
  • Impedance is purely imaginary.
  • No real power is consumed.
  • Energy is temporarily stored in the magnetic field.
  • The average power over one complete cycle is zero.

Power in a Pure Inductor

Instantaneous power is:

p(t)=v(t)i(t)p(t) = v(t)i(t)

Average power is:

P=VIcosϕP = VI\cos\phi

For a pure inductor,

ϕ=90\phi = 90^\circ

Since,

cos90=0\cos 90^\circ = 0

therefore,

P=0P = 0

Thus, a pure inductor consumes no average power.


Summary

  • In a pure inductor, current lags voltage by 9090^\circ.
  • Voltage leads current by 9090^\circ.
  • The inductive reactance is:
XL=ωLX_L = \omega L
  • The impedance of an inductor is:
Z=jωLZ = j\omega L
  • A pure inductor stores energy in its magnetic field.
  • The average power consumed by a pure inductor is zero.

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